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Acoustics · Wave propagation

Longitudinal wave speed

Over the same distance, which pulse arrives first?

Compare longitudinal pulses in two equal-length materials and see how wave speed changes their first-arrival times.

Try the interactive demo

Start with something familiar

Think of a row of people passing a brief push down the line. The disturbance can arrive at the far end while each person moves only a little. A wave travels; the material does not have to travel with it.

c = 5000 m/s

Progress after 0.20 ms

L = 1 m · t = 0.20 ms

c = 2500 m/s

Progress after 0.20 ms

L = 1 m · t = 0.40 ms

Diagram · Two equal paths, two arrival times. The marked particles stay near their own positions instead of travelling with the pulse.
  1. Notice what changes

    Separate local motion from travel. For a longitudinal wave, tiny back-and-forth particle motion is aligned with the direction the disturbance travels.

  2. Understand why

    With equal distance, a faster wave arrives earlier. With equal speed, a longer path takes longer. Transit time tells us about propagation, not directly about a vibration’s pitch.

  3. Connect it to wood and making

    In the axial rod approximation, elasticity resists compression while density supplies inertia. Their ratio sets the wave-speed scale. Bending and the assembled violin add geometry and different wave behaviour.

Put names to the ideas

01

Distance, speed and time

Travel time is t = L/c. With distance L fixed, doubling wave speed c halves the travel time. This compares propagation, not ring duration.

02

The disturbance travels

In a longitudinal wave, particles oscillate locally along the direction of propagation. They do not travel from one end to the other with the pulse.

03

Longitudinal and bending waves

Longitudinal speed describes axial stretching and compression. Bending waves also depend on thickness, frequency and direction; the two speeds are different quantities.

t=Lc,cL≈EL′ρt=\frac{L}{c},\qquad c_L\approx\sqrt{\frac{E'_L}{\rho}}

t = L/c says “time equals distance divided by speed.” In c = √(E′/ρ), increasing E′ at fixed density raises speed; increasing density at fixed E′ lowers it.

A worked example

Over 1 m, a 5000 m/s pulse takes 0.20 ms while a 2500 m/s pulse takes 0.40 ms. The animation is slowed and the particle displacement exaggerated so the travel can be inspected.

Explore it yourself

Change A’s wave speed, compare the arrival times, then use equal speed or replay to observe both pulses starting together.

Check your understanding

If speed doubles and distance stays fixed, what happens to travel time?

References